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(TFT) The bigger they are, the harder they fall
(Those with proportional fonts, turn back now.)
The recent giant article mentioned the concept of falling damage from
giants. In particular, it mentioned falling into an adjacent hex,
which works fine for one-hex giants:
___ ___
/ \ / \ / \
/ \___/ 1 \___/ \
\ / \ / \ /
\___/ 6 \___/ 2 \___/
/ \ / \ / \
/ \___/ G \___/ \
\ / \ / \ /
\___/ 5 \___/ 3 \___/
/ \ / \ / \
/ \___/ 4 \___/ \
\ / \ / \ /
\___/ \___/ \___/
/ \ / \ / \
/ \___/ \___/ \
\ / \ / \ /
\___/ \___/ \___/
But what about the three-hexers?
___ ___
/ \ / \ / \
/ \___/ \___/ \
\ / \ / \ /
\___/ \___/ \___/
/ \ / \ / \
/ \___/ G \___/ \
\ / \ / \ /
\___/ \___/ G \___/
/ \ / \ / \
/ \___/ G \___/ \
\ / \ / \ /
\___/ \___/ \___/
/ \ / \ / \
/ \___/ \___/ \
\ / \ / \ /
\___/ \___/ \___/
I was thinking that when such a giant falls, he
then occupies five hexes, as shown below:
___ ___
/ \ / \ / \
/ \___/ \___/ \
\ / \ / \ /
\___/ F \___/ \___/
/ \ / \ / \
/ \___/ G \___/ \
\ / \ / \ /
\___/ F \___/ G \___/
/ \ / \ / \
/ \___/ G \___/ \
\ / \ / \ /
\___/ \___/ \___/
/ \ / \ / \
/ \___/ \___/ \
\ / \ / \ /
\___/ \___/ \___/
When one falls down you can generate a number
from 1 to 4 to see what pair of hexes are hit:
___ ___
/ \ / \ / \
/ \___/ \___/ \
\ / \ / \ /
\___/ 1 \___/ 2 \___/
/ \ / \ / \
/ \___/ G \___/ 2 \
\ / \ / \ /
\___/ 1 \___/ G \___/
/ \ / \ / \
/ \___/ G \___/ 3 \
\ / \ / \ /
\___/ 4 \___/ 3 \___/
/ \ / \ / \
/ \___/ 4 \___/ \
\ / \ / \ /
\___/ \___/ \___/
So, is this workable?
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