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*To*: tft@brainiac.com*Subject*: Re: (TFT) Number Crunching: Example*From*: dwtulloh@zianet.com (Dan Tulloh)*Date*: Wed, 26 Jul 2000 01:51:18 -0400*Delivered-to*: alias-outgoing-tft@brainiac.com@outgoing*Reply-to*: tft@brainiac.com*Sender*: tft-owner@brainiac.com

John writes: > >What if I say, "OK, you defend. In my left hand are the three dice >I will accept as my hit and I won't bother throwing the one in my >right hand because it won't count. This becomes the same as Joe not >having defended at all. Ok, there's a misunderstanding here. Joe throws 4 dice and then takes the highest 3 of those thrown. Suppose Joe throws the following: 3, 2, 4, 5. Under the TFT system, the total of the dice thrown is 14. Under my system, the total is 12 (3+4+5). Since you don't know beforehand which 3 dice will be the highest, you can't exclude the other die. Is this any clearer? Dan > >Also, say an IQ roll is needed by Farsighted Ned to see the pit >trap and he gets his roll at 6D6. Does this mean that the GM rolls >6 dice, chooses three of those dice and that is the result (taking >into consideration crits and misses?) Sort of, but the GM doesn't get to pick which 3. The 3 chosen are the maximums of those thrown. If Ned rolls a 2, 5, 3, 1, 4, 6 then the maximums are 4, 5 and 6. So the roll is a 15. >Now what about a talent that lets a character defend better? Say, >add another Die to make it 5D6. Or what about a talent that lets >him immediately counter an attack that he defended: Sam defends, >Joe misses or hits, Sam immediately uses his counterattack skill >at -4DX. If 5 dice are thrown, you just take the highest 3 of those thrown. The real beauty of this system comes in on things like Naturalist (I think it is) where the character gets to throw 2 less die to notice something. Lets say there's a situation where a character needs 3d6 to notice something. A Naturalist would only have to throw 1 die which results in an AUTOMATIC success! In this case, the number of dice needed is less than 3. So how does the system work in this case? Ok ... 1 is 2 less than 3. Throw 2 extra dice (5 total) but, in this case, you would select the MINIMUM of those thrown. So if the throw is 4, 6, 2, 3, 3 then the minimums are 2, 3 and 3 ... so the total is 8. I hope this helps. Dan ===== Post to the entire list by writing to tft@brainiac.com. Unsubscribe by mailing to majordomo@brainiac.com with the message body "unsubscribe tft"

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