Re: (TFT) Replies to recent topics

["David Michael Grouchy II" <david_michael_grouchy_ii@hotmail.com>]

> From: Thorn <edt@dopey.ne.mediaone.net>
>
> Anyone up for launching a demon into orbit?
>
> Questions for the class:  How many transits, (T), of a 1000-foot drop
> shaft would an object need to make to achieve Earth-normal escape
> velocity, assuming Earth-normal gravitational acceleration?  Given T
> from above, assuming Gate instability beginning on the 100th transit of
> any particular gate, and taking into account the one-minute period of
> gate function despite instability, derive number of Gate pairs, (G),
> needed to attain T.  Given G from above, assuming Guild-standard 25-ST
> working days, and two apprentices per master, derive number of
> master/days to produce G.  Show all work.

   When falling from great altitudes the air is not as dence as it is at 
sea level and provides less resistance against the rate of acceleration.  
This is called ?Free air correction? and it is ?0.0003086 cm per second 
squared per meter traveled.  So if we start with the first gate at an 
altitude of 900m we get a correction of ?0.2469.
   Hahaha.  No really.  But it doesn?t matter.  A demon has an MA that is 
infinite.  Therefore it has to be frictionless.  Talk about your slippery 
floor.  Anything but a demon couldn?t achieve escape velocity.  Not by 
falling to the planet it was trying to escape.  The same force accelerating 
it would be holding it back once it left that last gate on its way up.
   In addition, anything that can achieve infinite MA in 5 seconds can 
propel itself into orbit.  Why would it need gate pairs?  But enough of 
theory.  I want my extra credit.

   Escape velocity is defined as 11,200 meters a second
   T is defined as transit of 1000 (feet?) vertically between two gates.  
Exiting one and falling into the next.
   G is defined as gate pairs.  In T above, two gate pairs are required.  
One to get the  figure to altitude, and one to catch them.

   The answer is T=1 and G=2.

   The work
One gate on the ground.  Flat on the ground.  When a figure steps onto it 
they fall out of a gate 1005ft up above it.  5ft above the ground is another 
horizontal gate.  The rule on this gate is that it does not activate unless 
the object is going escape velocity.  The other end of this gate is as high 
as possible and pointed up.


> For extra credit: Volunteer to ride that puppy, so we can open a Gate at
> apogee.  Volunteers should be able to answer the following question:
>
> Will the Gate created in orbit be geosynchronous?  Explain if not, and
> describe.


    No.  The earth will speed away from the gate at 29,750 meters a second. 
 Describe, you say?  Look at it this way.  What is easier, to travel 10 min 
back in time or 1 year.
    One year of course.  In 10 min the earth will have moved 1785 km.  But 
in a year it will right back here.  Each gate is locked to the center of 
gravity of the object it was created on.  If a gate is created not on the 
moon, and not on the earth, but in a space between, then it is considered 
still within the sun?s atmosphere.  Just like a gate 150km off the surface 
of the earth would be.
    The Sun?s galactic velocity is 250km a second.  This means the sun is 
moving relative to the galaxy that fast.  The galaxy us moving relative to 
the universe.  It goes on and on.  Unless a gate can ?ride? on another body, 
or in its relative atmosphere, it will be unattached, and be left behind.
    Now a question for you.  Can a gate 144,000 years old be waiting out 
there for us to orbit into it?  Do gates suffer from re-entry?

    David Michael Grouchy II




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