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Re: (TFT) Question to list --> contests.



Gah. In my last post I forgot that dividing the penalty breaks the symmetry. 

Therefore an alternative suggestion: Both sides roll N dice, and add the 
amount of [attribute] over 10 to the total (e.g. if rolling a St contest, a 
character with St 14 would add +4 to the total rolled). Highest total wins the 
contest. 

The N dice is a parameter adjusted by the GM to produce the right level of 
advantage to the stronger side. The higher N is, the closer to an even chance 
the weaker figure has. Try rolling 4 dice on each side (N = 4), adding the bonus 
for [attribute] over 10, and seeing how that works out. It ought to do better 
than your Method 2 at giving the weak side a better chance. 

Erol K. Bayburt
ErolB1@aol.com
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