David On Mar 15, 2008, at 8:40 PM, Paul MacDonald wrote:
pvk@oz.net wrote:My first shot would be like this: 1. Approximate Earth radius to say 6,360,000 meters.2. Observe that with conical hexes, hex length will be proportional to circumference of the sphere, which is the same as the circumference of acircle of radius R. Circumference = Radius x 2 x pi. So hex length is proportional to altitude above the center of the earth.3. So hex length (L) = altitdue above sea level (ASL) + 6,360,000 meters /6,360,000 meters.4. So at 0 ASL. L = 1 standard hex length. At 80,000m ASL, L = (6,360,000+ 80,000) / 6,360,000, = 1.0126 x standard hex length.At that point, I think I'd decide it was close enough and not worry aboutadding hexes as I ascended.It seems to me that at a certain distance you could use a megahex of the lower altitudes hexes to fill the current altitudes hex. I'm to drunk to figure it out at the moment, though.Paul -- What you own is your own kingdom What you do is your own glory What you love is your own power What you live is your own story Neil Peart ===== Post to the entire list by writing to tft@brainiac.com. Unsubscribe by mailing to majordomo@brainiac.com with the message body "unsubscribe tft"
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