RE: (TFT) Hex

["Jay Carlisle" <selfinflicted_wounds@boardermail.com>]

Again David, very nice stuff.

Again my thinking...

Useing like triangles "back of the envelope" math I get about 2.5 miles visability at sea level, everything else being optimal. Add 20ft and I get about 6 miles. 
300ft altitude is around 23 miles visability(radius)
3500ft (a tall hill, Weathertop?) 80 miles
16,000ft 165 mile visability. 330 mile circumfrance.


> From: "David Michael Grouchy II" <david_michael_grouchy_ii@hotmail.com>
> Date: Sat, 1 Sep 2007 03:19:31 -0500
> 
> 
> > selfinflicted_wounds@boardermail.com
> 
> >
> 
> > Exercise for the class; At what altitude do I need to be to where a hexgrid
> laid over the map contains 40m hexes measured side to side?
> 
> 
> Thirty hexes.*
> 
> David Michael Grouchy II
> 
> 
> 
> 
> 
> 
> 
> 
> 
> 
> The math part
> 
> =================================================
> 
> Optically figures appear their size divided by the distance.
> 
> apparent Size = size / z
> 
> a hex that is 1.333 m to a side
> 
> to optically contain an area 40 m to a side...
> 
> 40 / hex size = z
> 
> 40 / 1.333 = z
> 
> 40 / 1.333 = 30;
> 
> z = 30;
> 
> 40 / 30 = 1.333
> 
> ===================================================


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